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CGP EDU Academic Team
Published on: September 12, 2026
A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T. If the mass is increased by m then the time period becomes $\left(\frac{5}{4} \mathrm{T}\right)$ . The ratio of $\mathbf{T} \frac{p}{p-1}$ is
Text Solution
Verified by ExpertsThe correct answer is:
A
$T = 2\pi \sqrt{\frac{m}{k}}$ ⇒ ⇒ $m \propto T^{2}$ ⇒ ⇒ $\frac{m_2}{m_1} = \frac{T_2^2}{T_1^2}$
$\Rightarrow \frac{M+m}{M} = \left(\frac{\frac{5}{4}T}{T}\right)^2 \Rightarrow \frac{m}{M} = \frac{9}{16}$
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